怎么使用PHP查询两个表并将其合并

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首先,我们需要创建两个表并在表中插入一些数据。假设一个表名为“orders”,另一个表名为“customers”。orders表包括订单数据,包括订单号、订单日期、订单客户等等。而customers表则是客户数据,包括客户姓名、客户地址、客户电话等等。为了展示如何查询这两个表,我们创建如下表结构:

orders表

order_id order_date customer_id
1 2021-01-01 1
2 2021-01-02 2
3 2021-01-03 1
4 2021-01-04 3

customers表

customer_id customer_name customer_address customer_phone
1 Alice New York 123-456-7890
2 Bob Los Angeles 234-567-8901
3 Charlie Chicago 345-678-9012
4 David Houston 456-789-0123

接下来,我们将使用PHP查询这两个表,并将其合并成一个表,以便于我们对数据进行操作。以下是示例代码:

// Connect to database
$host = "localhost";
$user = "username";
$password = "password";
$database = "database";
$connect = mysqli_connect($host, $user, $password, $database);

// Query orders table
$query = "SELECT * FROM orders";
$result = mysqli_query($connect, $query);

// Query customers table
$query = "SELECT * FROM customers";
$result2 = mysqli_query($connect, $query);

// Merge two tables
$merged_array = array();
while ($row = mysqli_fetch_assoc($result)) {
    $customer_id = $row['customer_id'];
    $customer_query = "SELECT * FROM customers WHERE customer_id = $customer_id";
    $customer_result = mysqli_query($connect, $customer_query);
    $customer_row = mysqli_fetch_assoc($customer_result);
    $merged_array[] = array_merge($row, $customer_row);
}

// Show merged table
echo "<table>";
echo "<tr><th>Order ID</th><th>Order Date</th><th>Customer Name</th><th>Customer Address</th><th>Customer Phone</th></tr>";
foreach ($merged_array as $row) {
    echo "<tr>";
    echo "<td>" . $row['order_id'] . "</td>";
    echo "<td>" . $row['order_date'] . "</td>";
    echo "<td>" . $row['customer_name'] . "</td>";
    echo "<td>" . $row['customer_address'] . "</td>";
    echo "<td>" . $row['customer_phone'] . "</td>";
    echo "</tr>";
}
echo "</table>";

在上面的代码中,首先连接到数据库,然后查询orders和customers表,将结果存储到$result和$result2变量中。接下来,我们使用while循环和array_merge函数将两个表合并。在每个循环中,我们首先从orders表中获取特定行的customer_id,然后查询customers表以获取该客户的详细信息。最后,我们将两个数组合并,并将其添加到$merged_array变量中。最后,我们使用foreach循环在HTML表格中显示合并的表。

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